-16x^2+30=15-8x

Solution for -16x^2+30=15-8x equation:

-16x^2+30=15-8x

We move all terms to the left:

-16x^2+30-(15-8x)=0

We add all the numbers together, and all the variables

-16x^2-(-8x+15)+30=0

We get rid of parentheses

-16x^2+8x-15+30=0

We add all the numbers together, and all the variables

-16x^2+8x+15=0

a = -16; b = 8; c = +15;
Δ = b2-4ac
Δ = 82-4·(-16)·15
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*-16}=\frac{-40}{-32}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*-16}=\frac{24}{-32}
=-3/4
$